std::unordered_set::begin, std::unordered_set::cbegin
From cppreference.com
< cpp | container | unordered set
iterator begin(); |
(since C++11) | |
const_iterator begin() const; |
(since C++11) | |
const_iterator cbegin() const; |
(since C++11) | |
Returns an iterator to the first element of the container.
If the container is empty, the returned iterator will be equal to end().
Parameters
(none)
Return value
Iterator to the first element
Exceptions
noexcept specification:
noexcept
Complexity
Constant
Example
Run this code
#include <iostream> #include <unordered_set> struct Point { double x, y; }; int main() { Point pts[3] = { {1, 0}, {2, 0}, {3, 0} }; //points is a set containing the addresses of points std::unordered_set<Point *> points = { pts, pts + 1, pts + 2 }; //Change each y-coordinate of (i, 0) from 0 into i^2 and print the point for(auto iter = points.begin(); iter != points.end(); ++iter){ (*iter)->y = ((*iter)->x) * ((*iter)->x); //iter is a pointer-to-Point* std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") "; } std::cout << '\n'; //Now using the range-based for loop, we increase each y-coordinate by 10 for(Point * i : points) { i->y += 10; std::cout << "(" << i->x << ", " << i->y << ") "; } }
Possible output:
(3, 9) (1, 1) (2, 4) (3, 19) (1, 11) (2, 14)
See also
returns an iterator to the end (public member function) |