std::make_unsigned
From cppreference.com
Defined in header <type_traits>
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template< class T > struct make_unsigned; |
(since C++11) | |
If T
is an integral (except bool) or enumeration type, provides the member typedef type
which is the unsigned integer type corresponding to T
, with the same cv-qualifiers.
Otherwise, the behavior is undefined.
Member types
Name | Definition |
type
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the unsigned integer type corresponding to T
|
Helper types
template< class T > using make_unsigned_t = typename make_unsigned<T>::type; |
(since C++14) | |
Example
Run this code
#include <iostream> #include <type_traits> int main() { typedef std::make_unsigned<char>::type char_type; typedef std::make_unsigned<int>::type int_type; typedef std::make_unsigned<volatile long>::type long_type; bool ok1 = std::is_same<char_type, unsigned char>::value; bool ok2 = std::is_same<int_type, unsigned int>::value; bool ok3 = std::is_same<long_type, volatile unsigned long>::value; std::cout << std::boolalpha << "char_type is 'unsigned char'? : " << ok1 << '\n' << "int_type is 'unsigned int'? : " << ok2 << '\n' << "long_type is 'volatile unsigned long'? : " << ok3 << '\n'; }
Output:
char_type is 'unsigned char'? : true int_type is 'unsigned int'? : true long_type is 'volatile unsigned long'? : true
See also
(C++11) |
checks if a type is signed arithmetic type (class template) |
(C++11) |
checks if a type is unsigned arithmetic type (class template) |
(C++11) |
makes the given integral type signed (class template) |