std::literals::chrono_literals::operator""min
From cppreference.com
Defined in header <chrono>
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constexpr chrono::minutes operator "" min(unsigned long long mins); |
(1) | (since C++14) |
constexpr chrono::duration</*unspecified*/, ratio<60,1>> operator "" min(long double mins); |
(2) | (since C++14) |
Forms a std::chrono::duration literal representing minutes.
1) integer literal, returns exactly std::chrono::minutes(mins)
2) floating-point literal, returns a floating-point duration equivalent to std::chrono::minutes
Parameters
minutes | - | the number of minutes |
Return value
The std::chrono::duration literal.
Possible implementation
constexpr std::chrono::minutes operator ""min(unsigned long long m) { return std::chrono::minutes(m); } constexpr std::chrono::duration<long double, std::ratio<60,1>> operator ""min(long double m) { return std::chrono::duration<long double, ratio<60,1>> (m); } |
Notes
These operators are declared in the namespace std::literals::chrono_literals
, where both literals
and chrono_literals
are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono
, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the duration classes, the duration literal operators become visible as well.
Example
Run this code
#include <iostream> #include <chrono> int main() { using namespace std::chrono_literals; auto lesson = 45min; auto halfmin = 0.5min; std::cout << "one lesson is " << lesson.count() << " minutes\n" << "half a minute is " << halfmin.count() << " minutes\n"; }
Output:
one lesson is 45 minutes half a minute is 0.5 minutes
See also
constructs new duration (public member function of std::chrono::duration ) |