std::literals::chrono_literals::operator""s
Defined in header <chrono>
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constexpr chrono::seconds operator "" s(unsigned long long secs); |
(1) | (since C++14) |
constexpr chrono::duration</*unspecified*/> operator "" s(long double secs); |
(2) | (since C++14) |
Forms a std::chrono::duration literal representing seconds.
Parameters
secs | - | the number of seconds |
Return value
The std::chrono::duration literal.
Possible implementation
constexpr std::chrono::seconds operator ""s(unsigned long long s) { return std::chrono::seconds(s); } constexpr std::chrono::duration<long double> operator ""s(long double s) { return std::chrono::duration<long double>(s); } |
Notes
These operators are declared in the namespace std::literals::chrono_literals
, where both literals
and chrono_literals
are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono
, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the duration classes, the duration literal operators become visible as well.
std::string also defines operator""s
, to represent literal objects of type std::string
, but it is a string literal: 10s is ten seconds, but "10"s is a two-character string.
Example
#include <iostream> #include <chrono> int main() { using namespace std::chrono_literals; auto halfmin = 30s; std::cout << "half a minute is " << halfmin.count() << " seconds\n" << "a minute and a half is " << (1min + 30s).count() << " seconds\n"; }
Output:
half a minute is 30 seconds a minute and a half is 90 seconds
See also
constructs new duration (public member function of std::chrono::duration ) |