std::floor
From cppreference.com
Defined in header <cmath>
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float floor( float arg ); |
(1) | |
double floor( double arg ); |
(2) | |
long double floor( long double arg ); |
(3) | |
double floor( Integral arg ); |
(4) | (since C++11) |
1-3) Computes the largest integer value not greater than
arg
. 4) A set of overloads or a function template accepting an argument of any integral type. Equivalent to 2) (the argument is cast to double).
Parameters
arg | - | floating point value |
Return value
If no errors occur, the largest integer value not greater than arg
, that is ⌊arg⌋, is returned.
Return value
Argument
Error handling
Errors are reported as specified in math_errhandling
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- The current rounding mode has no effect.
- If
arg
is ±∞, it is returned, unmodified - If
arg
is ±0, it is returned, unmodified - If arg is NaN, NaN is returned
Notes
FE_INEXACT may be (but isn't required to be) raised when rounding a non-integer finite value.
The largest representable floating-point values are exact integers in all standard floating-point formats, so this function never overflows on its own; however the result may overflow any integer type (including std::intmax_t), when stored in an integer variable.
Example
Run this code
#include <cmath> #include <iostream> int main() { std::cout << std::fixed << "floor(+2.7) = " << std::floor(+2.7) << '\n' << "floor(-2.7) = " << std::floor(-2.7) << '\n' << "floor(-0.0) = " << std::floor(-0.0) << '\n' << "floor(-Inf) = " << std::floor(-INFINITY) << '\n'; }
Output:
floor(+2.7) = 2.000000 floor(-2.7) = -3.000000 floor(-0.0) = -0.000000 floor(-Inf) = -inf
See also
nearest integer not less than the given value (function) | |
(C++11) |
nearest integer not greater in magnitude than the given value (function) |
(C++11)(C++11)(C++11) |
nearest integer, rounding away from zero in halfway cases (function) |
C documentation for floor
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